यह उपयोगकर्ता द्वारा दर्ज दिए गए सेट से लापता मान प्रदर्शित करेगा
Given : array = {88, 105, 3, 2, 200, 0, 10}; Output : 1 4-9 11-87 89-99
एल्गोरिदम
START STEP 1-> Take an array with elements, bool flag[MAX] to Fale, int i, j, n to size of array Step 2-> Loop For from I to 0 and i=0 Set flag[array[i]]=true End IF Step 3 -> End For Loop Step 4 -> Loop For from i to 0 and i End For Loop STOP
उदाहरण
#include#define MAX 100 int main(int argc, char const *argv[]) { int array[] = {88, 105, 3, 2, 200, 0, 10}; bool flag[MAX] = { false }; //Initializing all the values of flag as false int i, j, n; n = sizeof(array)/sizeof(array[0]); for (i = 0; i < n; i++) { if (array[i] < 100 && array[i]>=0) { flag[array[i]] = true; //Making the value of the elements present in an array as true, So missing will remain false } } for (i = 0; i < MAX; ++i) { if(flag[i] == false) { //Checking for false values j = i+1; //Giving the value of the next iteration while(j आउटपुट
यदि हम उपरोक्त प्रोग्राम चलाते हैं तो यह निम्नलिखित आउटपुट उत्पन्न करेगा
1 4-9 11-87 89-99
