बी + ट्री एक बाइनरी सर्च ट्री का सामान्यीकरण है जिसमें एक नोड में दो से अधिक बच्चे हो सकते हैं। यह मूल रूप से एक स्व-संतुलित ट्री डेटा संरचना है जो सॉर्ट किए गए डेटा को बनाए रखता है और लॉगरिदमिक समय में अनुक्रमिक पहुंच, खोजों, सम्मिलन और विलोपन की अनुमति देता है।
इसे एक बी-पेड़ के रूप में देखा जा सकता है जिसमें प्रत्येक नोड में केवल कुंजियाँ होती हैं और जिसके नीचे जुड़े पत्तों के साथ एक अतिरिक्त स्तर जोड़ा जाता है।
एल्गोरिदम
Begin function insert() to insert the nodes into the tree: Initialize x as root. if x is leaf and having space for one more info then insert a to x. else if x is not leaf, do Find the child of x that is going to to be traversed next. If the child is not full, change x to point to the child. If the child is full, split it and change x to point to one of the two parts of the child. If a is smaller than mid key in the child, then set x as first part of the child. Else second part of the child. End
उदाहरण कोड
#include<iostream>
using namespace std;
struct BplusTree {
int *d;
BplusTree **child_ptr;
bool l;
int n;
}*r = NULL, *np = NULL, *x = NULL;
BplusTree* init()//to create nodes {
int i;
np = new BplusTree;
np->d = new int[6];//order 6
np->child_ptr = new BplusTree *[7];
np->l = true;
np->n = 0;
for (i = 0; i < 7; i++) {
np->child_ptr[i] = NULL;
}
return np;
}
void traverse(BplusTree *p)//traverse tree {
cout<<endl;
int i;
for (i = 0; i < p->n; i++) {
if (p->l == false) {
traverse(p->child_ptr[i]);
}
cout << " " << p->d[i];
}
if (p->l == false) {
traverse(p->child_ptr[i]);
}
cout<<endl;
}
void sort(int *p, int n)//sort the tree {
int i, j, t;
for (i = 0; i < n; i++) {
for (j = i; j <= n; j++) {
if (p[i] >p[j]) {
t = p[i];
p[i] = p[j];
p[j] = t;
}
}
}
}
int split_child(BplusTree *x, int i) {
int j, mid;
BplusTree *np1, *np3, *y;
np3 = init();
np3->l = true;
if (i == -1) {
mid = x->d[2];
x->d[2] = 0;
x->n--;
np1 = init();
np1->l = false;
x->l = true;
for (j = 3; j < 6; j++) {
np3->d[j - 3] = x->d[j];
np3->child_ptr[j - 3] = x->child_ptr[j];
np3->n++;
x->d[j] = 0;
x->n--;
}
for (j = 0; j < 6; j++) {
x->child_ptr[j] = NULL;
}
np1->d[0] = mid;
np1->child_ptr[np1->n] = x;
np1->child_ptr[np1->n + 1] = np3;
np1->n++;
r = np1;
} else {
y = x->child_ptr[i];
mid = y->d[2];
y->d[2] = 0;
y->n--;
for (j = 3; j <6 ; j++) {
np3->d[j - 3] = y->d[j];
np3->n++;
y->d[j] = 0;
y->n--;
}
x->child_ptr[i + 1] = y;
x->child_ptr[i + 1] = np3;
}
return mid;
}
void insert(int a) {
int i, t;
x = r;
if (x == NULL) {
r = init();
x = r;
} else {
if (x->l== true && x->n == 6) {
t = split_child(x, -1);
x = r;
for (i = 0; i < (x->n); i++) {
if ((a >x->d[i]) && (a < x->d[i + 1])) {
i++;
break;
} else if (a < x->d[0]) {
break;
} else {
continue;
}
}
x = x->child_ptr[i];
} else {
while (x->l == false) {
for (i = 0; i < (x->n); i++) {
if ((a >x->d[i]) && (a < x->d[i + 1])) {
i++;
break;
} else if (a < x->d[0]) {
break;
} else {
continue;
}
}
if ((x->child_ptr[i])->n == 6) {
t = split_child(x, i);
x->d[x->n] = t;
x->n++;
continue;
} else {
x = x->child_ptr[i];
}
}
}
}
x->d[x->n] = a;
sort(x->d, x->n);
x->n++;
}
int main() {
int i, n, t;
cout<<"enter the no of elements to be inserted\n";
cin>>n;
for(i = 0; i < n; i++) {
cout<<"enter the element\n";
cin>>t;
insert(t);
}
cout<<"traversal of constructed B tree\n";
traverse(r);
} आउटपुट
enter the no of elements to be inserted 10 enter the element 10 enter the element 20 enter the element 30 enter the element 40 enter the element 50 enter the element 60 enter the element 70 enter the element 80 enter the element 90 enter the element 100 traversal of constructed B tree 10 20 30 40 50 60 70 80 90 100