C प्रोग्राम: दो समय अवधियों का अंतर निकालना

समस्या

शुरुआत और समाप्ति समय (घंटे, मिनट, सेकंड) दर्ज करें और उनका अंतर निकालें।

लॉजिक

सेकंड्स और मिनट्स में उधार (बोरो) लेकर घटाव करें।

while(stop.sec > start.sec) {
    start.min--;
    start.sec += 60;
}
diff.sec = start.sec - stop.sec;

while(stop.min > start.min) {
    start.hrs--;
    start.min += 60;
}
diff.min = start.min - stop.min;
diff.hrs = start.hrs - stop.hrs;

C प्रोग्राम

#include <stdio.h>

struct time {
    int hrs, min, sec;
};

void diff_between_time(struct time start, struct time stop, struct time *diff);

int main() {
    struct time start_time, stop_time, diff;
    printf("Enter start time (hrs min sec): ");
    scanf("%d %d %d", &start_time.hrs, &start_time.min, &start_time.sec);
    printf("Enter stop time (hrs min sec): ");
    scanf("%d %d %d", &stop_time.hrs, &stop_time.min, &stop_time.sec);
    diff_between_time(start_time, stop_time, &diff);
    printf("Time Diff: %02d:%02d:%02d - %02d:%02d:%02d = %02d:%02d:%02d\n",
           start_time.hrs, start_time.min, start_time.sec,
           stop_time.hrs, stop_time.min, stop_time.sec,
           diff.hrs, diff.min, diff.sec);
    return 0;
}

void diff_between_time(struct time start, struct time stop, struct time *diff) {
    while (stop.sec > start.sec) {
        start.min--;
        start.sec += 60;
    }
    diff->sec = start.sec - stop.sec;
    while (stop.min > start.min) {
        start.hrs--;
        start.min += 60;
    }
    diff->min = start.min - stop.min;
    diff->hrs = start.hrs - stop.hrs;
}

आउटपुट

Enter start time: 12 45 57
Enter stop time: 20 35 20
Time Diff: 12:45:57 - 20:35:20 = -08:10:37

नोट

यदि स्टॉप टाइम स्टार्ट टाइम से पहले है, तो परिणाम नेगेटिव होगा। वास्तविक उपयोग में निरपेक्ष अंतर या 24-घंटे रैप-अराउंड हैंडल करें।

बेहतर दृष्टिकोण: कुल सेकंड्स में बदलें

int to_seconds(struct time t) {
    return t.hrs * 3600 + t.min * 60 + t.sec;
}

void diff_time(struct time t1, struct time t2, struct time *diff) {
    int sec1 = to_seconds(t1);
    int sec2 = to_seconds(t2);
    int diff_sec = sec1 - sec2; // या abs(sec1 - sec2)
    diff->hrs = diff_sec / 3600;
    diff_sec %= 3600;
    diff->min = diff_sec / 60;
    diff->sec = diff_sec % 60;
}