इस समस्या में हम दो उपयोगकर्ता इनपुट सूची का उपयोग करते हैं। हमारा काम यह जांचना है कि कहीं कोई कॉमन एलिमेंट तो नहीं है। हम बहुत ही सरल ट्रैवर्सिंग तकनीक का उपयोग करते हैं, दोनों सूची को पार करते हैं और पहली सूची और दूसरी सूची के प्रत्येक तत्व की जांच करते हैं।
उदाहरण
Input : A = [10, 20, 30, 50] B = [90, 80, 30, 10, 3] Output : FOUND Input : A = [10, 20, 30, 50] B = [100,200,300,500] Output : NOT FOUND
एल्गोरिदम
commonelement(A,B) /* A and B are two user input list */ Step 1: First use one third variable c which is display the result. Step 2: Traverse both the list and compare every element of the first list with every element of the second list. Step 3: If common element is found then c display FOUND otherwise display NOT FOUND.
उदाहरण कोड
# Python program to check # if two lists have at-least # one element common # using traversal of list def commonelement(A, B): c = "NOT FOUND" # traverse in the 1st list for i in A: # traverse in the 2nd list for j in B: # if one common if i == j: c="FOUND" return c return c # Driver code A=list() B=list() n1=int(input("Enter the size of the first List ::")) print("Enter the Element of first List ::") for i in range(int(n1)): k=int(input("")) A.append(k) n2=int(input("Enter the size of the second List ::")) print("Enter the Element of second List ::") for i in range(int(n2)): k=int(input("")) B.append(k) print("Display Result ::",commonelement(A, B))
आउटपुट
Enter the size of the first List ::4 Enter the Element of first List :: 2 1 4 9 Enter the size of the second List ::5 Enter the Element of second List :: 9 90 4 89 67 Display Result :: FOUND Enter the size of the first List ::4 Enter the Element of first List :: 67 89 45 23 Enter the size of the second List ::4 Enter the Element of second List :: 1 2 3 4 Display Result :: NOT FOUND