पायथन में घंटे मिनट के समय को टेक्स्ट फॉर्मेट में बदलने का प्रोग्राम

मान लीजिए हमारे पास दो इनपुट hour और minutes हैं। हमें समय को टेक्स्ट फॉर्मेट में दिखाना है। यह इस तरह है:

8:00 : 8 बजे
8:01 : आठ के बाद एक मिनट
8:10 : आठ के बाद दस मिनट
8:15 : आठ के बाद क्वार्टर
8:30 : आठ के बाद आधा
8:40 : नौ से पहले बीस मिनट
8:45 : नौ से पहले क्वार्टर
8:47 : नौ से पहले तेरह मिनट
8:28 : आठ के बाद अट्ठाईस मिनट

उदाहरण के लिए, यदि इनपुट h = 9, m = 42 है, तो आउटपुट दस से पहले अठारह मिनट होगा।

हल करने के चरण

text := 30 अलग-अलग न्यूमेरिक मानों के लिए टेक्स्ट वाली सूची: ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "quarter", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", "twenty-one", "twenty-two", "twenty-three", "twenty-four", "twenty-five", "twenty-six", "twenty-seven", "twenty-eight", "twenty-nine", "half"]
op := खाली स्ट्रिंग
यदि m == 0, तो op := text[h - 1] + " o' clock"
अन्यथा यदि m == 30, तो op := text[m - 1] + " past " + text[h - 1]
अन्यथा यदि m == 1, तो op := text[m - 1] + " minute past " + text[h - 1]
अन्यथा यदि m == 15, तो op := text[m - 1] + " past " + text[h - 1]
अन्यथा यदि m < 30, तो op := text[m - 1] + " minutes past " + text[h - 1]
अन्यथा यदि m == 45, तो op := "quarter to " + text[h]
अन्यथा op := text[(60 - m) - 1] + " minutes to " + text[h]
op वापस करें।

उदाहरण

बेहतर समझ के लिए निम्नलिखित कार्यान्वयन देखें:

def solve(h, m):
    text = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine", "ten", "eleven", "twelve", "thirteen", "fourteen", "quarter", "sixteen", "seventeen", "eighteen", "nineteen", "twenty", "twenty-one", "twenty-two", "twenty-three", "twenty-four", "twenty-five", "twenty-six", "twenty-seven", "twenty-eight", "twenty-nine", "half"]
    op = ""
    if m == 0:
        op = text[h - 1] + " o' clock"
    elif m == 30:
        op = text[m - 1] + " past " + text[h - 1]
    elif m == 1:
        op = text[m - 1] + " minute past " + text[h - 1]
    elif m == 15:
        op = text[m - 1] + " past " + text[h - 1]
    elif m < 30:
        op = text[m - 1] + " minutes past " + text[h - 1]
    elif m == 45:
        op = "quarter to " + text[h]
    else:
        op = text[(60 - m) - 1] + " minutes to " + text[h]
    return op

h = 9
m = 42
print(solve(h, m))

इनपुट

9, 42

आउटपुट

eighteen minutes to ten